在下面的程序中,我们根据给定的n和r值计算 nPr 的值。 nPr 也可以表示为P(n, r)。P(n, r)的公式是n! /(n - r)!,例如 P(6, 2)= 6! /(6-2)! => 720/24 = 30。我们在下面的 C 程序中实现了相同的逻辑。
#include <stdio.h>void main(){ int n, r, npr_var; printf("Enter the value of n:"); scanf("%d", &n); printf("\nEnter the value of r:"); scanf("%d", &r); /* nPr is also known as P(n,r), the formula is: * P(n,r) = n! / (n - r)! For 0 <= r <= n. */ npr_var = fact(n) / fact(n - r); printf("\nThe value of P(%d,%d) is: %d",n,r,npr_var);}// Function for calculating factorialint fact(int num){ int k = 1, i; // factorial of 0 is 1 if (num == 0) { return(k); } else { for (i = 1; i <= num; i++) { k = k * i; } } return(k);}输出:
Enter the value of n:5 Enter the value of r:2The value of P(6,2) is: 30
