该程序使用用户定义的函数将八进制数转换为二进制数。
示例:将八进制转换为二进制的程序
在这个程序中,我们创建了一个用户定义的函数octalToBinary()。此函数首先将八进制数(由用户输入)转换为十进制数,然后将该十进制数转换为二进制数。要了解该程序的工作原理,您应具备以下 C 编程主题的基本知识:
#include <stdio.h>#include <math.h>//This function converts octal number to binary numberlong octalToBinary(int octalnum){ int decimalnum = 0, i = 0; long binarynum = 0; /* This loop converts octal number "octalnum" to the * decimal number "decimalnum" */ while(octalnum != 0) { decimalnum = decimalnum + (octalnum%10) * pow(8,i); i++; octalnum = octalnum / 10; } //i is re-initialized i = 1; /* This loop converts the decimal number "decimalnum" to the binary * number "binarynum" */ while (decimalnum != 0) { binarynum = binarynum + (decimalnum % 2) * i; decimalnum = decimalnum / 2; i = i * 10; } //Returning the binary number that we got from octal number return binarynum;}int main(){ int octalnum; printf("Enter an octal number: "); scanf("%d", &octalnum); //Calling the function octaltoBinary printf("Equivalent binary number is: %ld", octalToBinary(octalnum)); return 0;}输出:
Enter an octal number: 71Equivalent binary number is: 111001
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