Java 实例 使用递归检查回文字符串

来源:这里教程网 时间:2026-02-17 20:16:49 作者:

程序:使用递归检查String是否为回文

package beginnersbook.com;import java.util.Scanner;class PalindromeCheck{    //My Method to check    public static boolean isPal(String s)    {   // if length is 0 or 1 then String is palindrome        if(s.length() == 0 || s.length() == 1)            return true;         if(s.charAt(0) == s.charAt(s.length()-1))        /* check for first and last char of String:         * if they are same then do the same thing for a substring         * with first and last char removed. and carry on this         * until you string completes or condition fails         * Function calling itself: Recursion         */        return isPal(s.substring(1, s.length()-1));        /* If program control reaches to this statement it means         * the String is not palindrome hence return false.         */        return false;    }    public static void main(String[]args)    {        //For capturing user input        Scanner scanner = new Scanner(System.in);        System.out.println("Enter the String for check:");        String string = scanner.nextLine();        /* If function returns true then the string is         * palindrome else not         */        if(isPal(string))            System.out.println(string + " is a palindrome");        else            System.out.println(string + " is not a palindrome");    }}

输出:

Enter the String for check:qqaabbqqaabb is not a palindrome

输出 2:

Enter the String for check:cocoococcocoococ is a palindrome

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