Java URI getHost()方法及示例

getHost()函数是URI类的一部分。函数getHost()返回指定URI的主机。
URL的Host部分是URI的主机名称。

函数签名:

public String getHost()

返回类型 该函数返回字符串类型

语法

url.getHost()

参数 ：该函数不需要任何参数

下面的程序将说明getHost()函数的使用 。

例1 :

// Java program to show the // use of the function getHost()  import java.net.*;class Solution {public static void main(String args[])    {        // URI  object        URI uri = null;          try {            // create a URI            uri = new URI("https://www.geeksforgeeks.org");              // get the Host            String host = uri.getHost();              // display the URI            System.out.println("URI = " + uri);              // display the Host            System.out.println("Host = " + host);        }        // if any error occurs        catch (URISyntaxException e) {            // display the error            System.out.println("URI Exception =" + e.getMessage());        }    }}

输出:

URI = https://www.geeksforgeeks.orgHost = www.geeksforgeeks.org

例2： getAuthority()和getHost()函数的区别在于，getAuthority()返回主机和端口，而getHost()只返回主机名。

// Java program to show the // use of the function getHost()  import java.net.*;  class Solution {    public static void main(String args[])    {        // url  object        URI uri = null;          try {            // create a URI            uri = new URI("https://www.geeksforgeeks.org:80");              // get the Authority            String authority = uri.getAuthority();              // get the Host            String host = uri.getHost();              // display the URI            System.out.println("URI = " + uri);              // display the Authority            System.out.println("Authority = " + authority);              // display the Host            System.out.println("Host = " + host);        }        // if any error occurs        catch (URISyntaxException e) {            // display the error            System.out.println("URI Exception =" + e.getMessage());        }    }}

输出:

URI = https://www.geeksforgeeks.org:80Authority = www.geeksforgeeks.org:80Host = www.geeksforgeeks.org