Guava – Longs.factorial方法与实例
Guava的LongMath类的factorial(int n)方法返回前n个正整数的乘积,也就是n!。
语法:
public static long factorial(int n)
参数: 该方法只接受一个参数 n ,该参数为整数类型,用于求阶乘。
返回值: 本方法返回以下数值。
本方法返回 1 if n is 0.本方法返回前n个正整数的乘积,如果结果适合于long。如果结果不在一个长条中,该方法返回 Long.MAX_VALUE 。异常情况: 阶乘(int n)方法如果n是负数,会产生IllegalArgumentException。
以下程序说明了LongMath.factorial()方法的使用。
示例1:
// Java code to show implementation of// factorial(int n) method of Guava's// LongMath Class import java.math.RoundingMode;import com.google.common.math.LongMath; class GFG { // Driver code public static void main(String args[]) { int n1 = 10; // Using factorial(int n) method of // Guava's LongMath class long ans1 = LongMath.factorial(n1); System.out.println("factorial of " + n1 + " is : " + ans1); int n2 = 12; // Using factorial(int n) method of // Guava's LongMath class long ans2 = LongMath.factorial(n2); System.out.println("factorial of " + n2 + " is : " + ans2); }}
输出:
factorial of 10 is : 3628800factorial of 12 is : 479001600
示例 2 :
// Java code to show implementation of// factorial(int n) method of Guava's// LongMath Class import java.math.RoundingMode;import com.google.common.math.LongMath; class GFG { static long findFact(int n) { try { // Using factorial(int n) method of // Guava's LongMath class // This should throw "IllegalArgumentException" // as n < 0 long ans = LongMath.factorial(n); // Return the answer return ans; } catch (Exception e) { System.out.println(e); return -1; } } // Driver code public static void main(String args[]) { int n = -5; try { // Function calling findFact(n); } catch (Exception e) { System.out.println(e); } }}输出:
java.lang.IllegalArgumentException: n (-5) must be >= 0
参考:
https://google.github.io/guava/releases/20.0/api/docs/com/google/common/math/LongMath.html#factorial-int-
