Java 实例 使用递归查找给定数字的阶乘

来源:这里教程网 时间:2026-02-17 20:16:50 作者:

在这里,我们将编写程序,使用递归找出数字的阶乘。

程序 1:

程序将提示用户输入数字。一旦用户提供输入,程序将计算所提供输入数的阶乘。

/** * @author: BeginnersBook.com * @description: User would enter the 10 elements * and the program will store them into an array and  * will display the sum of them. */import java.util.Scanner;class FactorialDemo{   public static void main(String args[]){      //Scanner object for capturing the user input      Scanner scanner = new Scanner(System.in);      System.out.println("Enter the number:");      //Stored the entered value in variable      int num = scanner.nextInt();      //Called the user defined function fact      int factorial = fact(num);      System.out.println("Factorial of entered number is: "+factorial);   }   static int fact(int n)   {       int output;       if(n==1){         return 1;       }       //Recursion: Function calling itself!!       output = fact(n-1)* n;       return output;   }}

输出:

Enter the number:5Factorial of entered number is: 120

程序 2:

如果您不想要用户干预并且只想在程序中指定数字,请参考此示例。

class FactorialDemo2{   public static void main(String args[]){      int factorial = fact(4);      System.out.println("Factorial of 4 is: "+factorial);   }   static int fact(int n)   {       int output;       if(n==1){         return 1;       }       //Recursion: Function calling itself!!       output = fact(n-1)* n;       return output;   }}

输出:

Factorial of 4 is: 24

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