该程序使用线性搜索算法，在用户输入的所有其他数字中找出数字。
/* Program: Linear Search Example * Written by: Chaitanya from beginnersbook.com * Input: Number of elements, element's values, value to be searched * 输出：Position of the number input by user among other numbers*/import java.util.Scanner;class LinearSearchExample{ public static void main(String args[]) { int counter, num, item, array[]; //To capture user input Scanner input = new Scanner(System.in); System.out.println("Enter number of elements:"); num = input.nextInt(); //Creating array to store the all the numbers array = new int[num]; System.out.println("Enter " + num + " integers"); //Loop to store each numbers in array for (counter = 0; counter < num; counter++) array[counter] = input.nextInt(); System.out.println("Enter the search value:"); item = input.nextInt(); for (counter = 0; counter < num; counter++) { if (array[counter] == item) { System.out.println(item+" is present at location "+(counter+1)); /*Item is found so to stop the search and to come out of the * loop use break statement.*/ break; } } if (counter == num) System.out.println(item + " doesn't exist in array."); }}
输出 1：
Enter number of elements:6Enter 6 integers2233451399Enter the search value:4545 is present at location 3
输出 2：
Enter number of elements:4Enter 4 integers112245Enter the search value:9999 doesn't exist in array.
