Java Instant minusNanos()方法及示例

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Java Instant minusNanos()方法及示例

Instant类minusNanos() 方法将作为参数的纳秒值从这个瞬间中减去,并将结果作为一个瞬间对象返回。这个返回的 Instant 是不可改变的。

语法:

public Instant minusNanos(long nanosToSubtract)

参数: 该方法接受一个参数 nanosToSubtract ,即要减去的纳秒数。

返回: 该方法返回减去纳秒数后的 Instant

异常: 该方法抛出以下异常:

DateTimeException :如果结果超过了最大或最小的瞬间。ArithmeticException :如果发生数字溢出。

以下程序说明了minusNanos()方法:

程序1:

// Java program to demonstrate// Instant.minusNanos() method import java.time.*; public class GFG {    public static void main(String[] args)    {         // create a Instant object        Instant instant            = Instant.parse("2018-12-30T19:34:50.63Z");         // current Instant        System.out.println("Initialize instant: "                           + instant);         // subtract 430000000 nanoseconds        // means .43 seconds from this instant        Instant returnedValue            = instant.minusNanos(430000000);         // print result        System.out.println("Returned Instant: "                           + returnedValue);    }}

输出

Initialize instant: 2018-12-30T19:34:50.630ZReturned Instant: 2018-12-30T19:34:50.200Z

程序2:

// Java program to demonstrate// Instant.minusNanos() method import java.time.*; public class GFG {    public static void main(String[] args)    {         // create a Instant object        Instant instant = Instant.now();         // current Instant        System.out.println("Current instant: "                           + instant);         // subtract 540000000 nanoseconds        // means .564 seconds from this instant        Instant returnedValue            = instant.minusNanos(540000000);         // print result        System.out.println("Returned Instant: "                           + returnedValue);    }}

输出

Current instant: 2018-11-27T06:43:58.495ZReturned Instant: 2018-11-27T06:43:57.955Z

参考文献: https://docs.oracle.com/javase/10/docs/api/java/time/Instant.html#minusNanos(long)

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