Java Instant minusNanos()方法及示例
Instant类 的 minusNanos() 方法将作为参数的纳秒值从这个瞬间中减去,并将结果作为一个瞬间对象返回。这个返回的 Instant 是不可改变的。
语法:
public Instant minusNanos(long nanosToSubtract)
参数: 该方法接受一个参数 nanosToSubtract ,即要减去的纳秒数。
返回: 该方法返回减去纳秒数后的 Instant 。
异常: 该方法抛出以下异常:
DateTimeException :如果结果超过了最大或最小的瞬间。ArithmeticException :如果发生数字溢出。以下程序说明了minusNanos()方法:
程序1:
// Java program to demonstrate// Instant.minusNanos() method import java.time.*; public class GFG { public static void main(String[] args) { // create a Instant object Instant instant = Instant.parse("2018-12-30T19:34:50.63Z"); // current Instant System.out.println("Initialize instant: " + instant); // subtract 430000000 nanoseconds // means .43 seconds from this instant Instant returnedValue = instant.minusNanos(430000000); // print result System.out.println("Returned Instant: " + returnedValue); }}
输出
Initialize instant: 2018-12-30T19:34:50.630ZReturned Instant: 2018-12-30T19:34:50.200Z
程序2:
// Java program to demonstrate// Instant.minusNanos() method import java.time.*; public class GFG { public static void main(String[] args) { // create a Instant object Instant instant = Instant.now(); // current Instant System.out.println("Current instant: " + instant); // subtract 540000000 nanoseconds // means .564 seconds from this instant Instant returnedValue = instant.minusNanos(540000000); // print result System.out.println("Returned Instant: " + returnedValue); }}输出
Current instant: 2018-11-27T06:43:58.495ZReturned Instant: 2018-11-27T06:43:57.955Z
参考文献: https://docs.oracle.com/javase/10/docs/api/java/time/Instant.html#minusNanos(long)
