Guava – Longs.contains()方法与实例
Guava的Longs类的Longs.contains()方法是用来检查一个值,即目标值是否存在于数组中。这个目标值和数组被作为该方法的参数。这个方法返回一个布尔值,说明目标值是否是
语法:
public static boolean contains(long[] array, long target)
参数: 这个方法接受两个参数。
array: 这是要搜索目标值的值数组target: 这是要检查是否存在的长值。返回值: 如果对于i的某个值,存在于i True 索引的值等于目标值,则该方法返回 th 异常情况。 False .
该方法不抛出任何异常。
示例1:
// Java code to show implementation of// Guava's Longs.contains() method import com.google.common.primitives.Longs;import java.util.Arrays; class GFG { // Driver's code public static void main(String[] args) { // Creating a long array long[] arr = { 5L, 4L, 3L, 2L, 1L }; long target = 3L; // Using Longs.contains() method to search // for an element in the array. The method // returns true if element is found, else // returns false if (Longs.contains(arr, target)) System.out.println("Target is present" + " in the array"); else System.out.println("Target is not " + "present in the array"); }}
输出:
Target is present in the array
示例2:
// Java code to show implementation of// Guava's Longs.contains() method import com.google.common.primitives.Longs;import java.util.Arrays; class GFG { // Driver's code public static void main(String[] args) { // Creating a long array long[] arr = { 2L, 4L, 6L, 8L, 10L }; long target = 7L; // Using Longs.contains() method to search // for an element in the array. The method // returns true if element is found, else // returns false if (Longs.contains(arr, target)) System.out.println("Target is present" + " in the array"); else System.out.println("Target is not " + "present in the array"); }}
输出:
Target is not present in the array
参考:
https://google.github.io/guava/releases/21.0/api/docs/com/google/common/primitives/Longs.html#contains-long:A-long-
